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Solution :

As `4` is a root of `x^2+px+12 = 0`,<br>
`:. x = 4` should satisfy the equation.<br>
`=>4^2+4p+12 = 0`<br>
`=>4p = -28`<br>
`=>p = -7`<br>
Now, `x^2+px+q` has equal roots,<br>
`:. D =0`<br>
`=>p^2 - 4q = 0`<br>
`=>(-7)^2 - 4q = 0`<br>
`=>4q = 49`<br>
`=>q = 49/4`<br>
So, option `(a)` is the correct option.<br>**What is Quadratic Equation ?**

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