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`30sqrt(2)`A60 A100 A`60sqrt(2)`A

Answer :

BSolution :

The impedance of the circuit is <br> Z = `sqrt R^(2) + (underset(L)(X)- underset(C )(X))^(2)` <br> `underset(L)(X)= omegaL = 400 xx 20 xx 10^(-3)= 8 H` <br> `X_(C)` = `1omegaC = 1/400 xx 625 xx 10^(-6)` = 4F <br> Z = `sqrt (3)^(2) + (8 - 4)^(2)` = 5 <br> I = `E/Z = 300/5 = 60 A`